five. Which on the following subnet masks are represented with the CIDR of /27? A. 255.255.255.254 B. 255.255.255.248 C. 255.255.255.224 D. 255.255.255.240 Answer: C. The CIDR /27 tells you that 27 ones are 70-680 turned on within the subnet mask. Twenty-seven 1s equals 11111111.11111111.11111111.11100000 . This would then equal 255.255.255.224 . 6. You administer a network that consists of 175 machines. Your manager has assigned the network the IP address 192.168.11. 0 together with the default subnet mask of 255.255.255.0. A router which has 1 WAN interface and eight LAN interfaces connects this network to the corporate WAN. You want to subnet the network into three subnets, and you need to reserve a few addresses for a fourth subnet, just in situation you need it later. You make a decision that Subnet A will contain 25 computers, Subnet B will include 50 computers, and Subnet C will include 100 computers. Inside the following exhibit, choose the network addresses and subnet masks in the Selections column, and place them inside the suitable boxes inside the other three columns. Every single item may very well be made use of only the moment. Answer: The network address 192.168.11.192 with a mcse 2008 subnet mask of 255.255.255.224 is wonderful for Subnet A since it supports as much as 30 hosts. The network address 192.168.11.128 using a subnet mask of 255.255.255.192 is excellent for Subnet B because it supports as much as 62 hosts. The network address 192.168.11.0 using a subnet mask of 255.255.255.128 is wonderful for Subnet C because it supports as much as 126 hosts.
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